A.9  Summations and integrals

Note that

( n=1Nx[n]) ( n=1Ny[n]) = n=1N m=1N (x[n]y[m])

because, e.g., (a + b + c)(d + e + f) = ad + ae + af + bd + be + bf + cd + ce + cf. Similarly, in the continuous-case

(T0x(t)dt) (T0y(t)dt) =T0T0 (x(t)y(s))dtds,

where one should note the adoption of distinct integration variables t and s. This result allows to express

(T0x(t)dt)2 =T0T0 (x(t)x(s))dtds,
(A.22)

which is an useful expression. Note that, in general,

(T0x(t)dt)2T0x2(t)dt.